vendredi 28 août 2020

reinterpret_cast - An expression of integral, enumeration, pointer, or pointer-to-member type can be converted to its own type

https://en.cppreference.com/w/cpp/language/reinterpret_cast

An expression of integral, enumeration, pointer, or pointer-to-member type can be converted to its own type. The resulting value is the same as the value of expression. (since C++11)

Why should I be interested in converting something to its own type? This reads to me as I would want to convert int to int.

Please correct me.

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