Why is it called operator overloading?

If the following class, Foo, is defined. It is said it overloads the unary ampersand (&) operator:

class Foo {
public:
   Foo* operator&() { return nullptr; }
};

I think in this case, (reglardless of he fact that you can get the address of such an object by means of std::addressof() and other idiomatic tricks) there is no way to access/choose the original unary ampersand operator that returns the address of the object called on, am I wrong?

By overloading however, I understand that there is a set of functions of which one will be seletected at compile-time based on some criateria. But this thinking doesn't seem to match the scenario above.

Why is it then called overloading and not something else like redefining or replacing?