samedi 24 juin 2017

Which C++ compiler gets called when running g++ without an std argument?

I have a piece of code that looks like the following. Let's say it's in a file named example.cpp

#include <fstream>
#include <string> // line added after edit for clarity

int main() {
    std::string filename = "input.txt";
    std::ifstream in(filename);

    return 0;
}

On a windows, if I type in the cmd the command g++ example.cpp, it will fail. It's a long list of errors I think mostly due to the linker complaining about not being able to convert from string to const char*.

But if I run the compiler using an additional argument like so: g++ -std=c++17 example.cpp, it will compile and work fine with no problems.

What happens when I run the former command? I'm guessing a default version of the C++ compiler gets called, but I don't know which? And as a programmer/developer, should I always use the latter command with the extra argument?

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