Storing a raw pointer returned from a method into a smart pointer

Scenario:
I am using a method from an old C++ library which returns a raw pointer to SomeClass where SomeClass is an exported class from a library header say SomeClass.h

Following is the signature of LibraryMethod that I am using:

SomeClass* LibraryMethod();

I don't have access to change the library. I am using only the binary & public header which is a typical scenario.

I dont want to use raw pointers in my part of the code. Hence, I have a shared pointer to SomeClass in my part of the code using the library API.

std::shared_ptr<SomeClass> some_class;

which I initialise like this to avoid storing a raw pointer to SomeClass

some_class = (std::shared_ptr<SomeClass>)LibraryMethod();

This basically works but I want to understand the details here

Question:
Is the above a correct technique ?
Am I causing a leak here ?
Are there any better techniques to handle such a scenario ?