name is not a typename. Defining struct with type inside using macros [duplicate]

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• Where and why do I have to put the “template” and “typename” keywords? 5 answers

Given the following:

#define createProp(label, m_tt)                                 \
template<> struct prop<Props::##label> { using type = m_ty; };

enum class Props;

template<Props Type>
struct prop;

enum class Props { Fullscreen, Borderless, };

createProp(Fullscreen, bool)

struct PropHolder {
    template<Props Type>
    void setProperty(prop<Type>::type value) { } //Error Here

    template<Props Type>
    prop<Type>::type getProperty() { } //Error here
};

When trying to compile it, the compiler will fail to recognize type in prop struct. Error list gives the warning 'prop<Type>::type': dependent name is not a type followed by the error syntax error: identifier 'type' (in lines marked by comments above).

Why isn't it a type? I've tried using both using type = m_ty and typedef m_ty type. Both of them are throwing the same error

Is the syntax error caused by the warning? Or did I misspell something? What should I do to preserve all setProperty, getProperty and createProp(...) as they are?

Also, how should I do so the macro also defines constexpr Props Prop_Fullscreen = Props::Fullscreen? Would constexpr Props Prop_##label = Props::##label work? I'm not sure how token-pasting works.