namespace specialization in template class

I have two different namespaces that implement identical methods and classes in two different ways. I am writing a class that used this methods and classes to do something, I was wondering if there was a way to declare the namespace without partial specialization as below:

#include <string>
#include <iostream>

namespace one
{
int test()
{
    return 1;
}
}

namespace two
{
int test()
{
    return 2;
}
}

enum names : int
{
    first = 1,
    second = 2
};

template <names>
struct base_class;

template <>
struct base_class<names::first>
{
    using namespace ::one;
};

template <>
struct base_class<names::second>
{
    using namespace ::two;
};

template <names ns>
struct delcare_namespace : public base_class<ns>
{
    delcare_namespace()
    {
        std::cout << test() << "\n";
    }
};

for the code above, I get

test’ was not declared in this scope