Variadic template, no matching function for call

I'm trying to use variadic template to refactor some of my code, but the compiler has "no matching function for call" error. Below is a simplified version (it may not make sense for functionality, but an example to reproduce the error):

// base case
void testFunc(int i) { std::cout << i << std::endl; }

template <class T, class... Args> void testFunc(int i) {
  T t = 0;
  std::cout << t << std::endl;
  testFunc<Args...>(i);
}

int main() {
  testFunc<int, long, float>(1);
  return 0;
}

The error messages:

main.cpp:9:3: error: no matching function for call to 'testFunc'
  testFunc<Args...>(i);
  ^~~~~~~~~~~~~~~~~
main.cpp:9:3: note: in instantiation of function template specialization 'testFunc<float>' requested here
main.cpp:9:3: note: in instantiation of function template specialization 'testFunc<long, float>' requested here
main.cpp:13:3: note: in instantiation of function template specialization 'testFunc<int, long, float>' requested here
  testFunc<int, long, float>(1);
  ^
main.cpp:6:40: note: candidate template ignored: couldn't infer template argument 'T'
template <class T, class... Args> void testFunc(int i) {
                                       ^
1 error generated.

It looks like that the unwrapping of template parameters is working, and stops at the base case. But I have defined the base case. Why there is no matching function?