How to propagate an undefined number of template arguments? [duplicate]

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• Variadic templates 8 answers

Using the following class, I would like to be able to create an instance of a specified Foo() to store and call a function, but how can I transmit the necessary arguments to a function call ?

template<class R, class... Args> class Foo {
    std::function<R(Args...)> func;

    Foo(const std::function<R(Args...)> &funcIn) : func(funcIn) {}

    R call(Args...) {
        return func(/* ? */);
    }
};

E.g:

int main() {
    typedef typename Foo<int(int)> Bar;
    Bar x([](int y, int z){return y + z + 2;});
    std::cout << x.call(12, 7);
    return 0;
}