Consider the following code. Here, if we use std::begin
on an unnamed initializer_list
with explicit std::
, it works OK. If we omit the std::
and use begin
on a named initializer_list
, it also works fine. But if we omit std::
and do the rest similarly to the first case, it fails to compile.
#include <iostream>
#include <iterator>
void func(int len, const int* x)
{
for(int i=0;i<len;++i)
std::cout << x[i] << "\n";
}
int main()
{
{
// OK
func(5, std::begin({1,3,6,823,-35}));
}
{
// OK
auto&& list = {1,3,6,823,-35};
func(5, begin(list));
}
// {
// // Fails to compile
// func(5, begin({1,3,6,823,-35}));
// }
}
I get the following compilation error (after I uncomment the faulty code):
test.cpp: In function ‘int main()’:
test.cpp:21:11: error: ‘begin’ was not declared in this scope
func(5, begin({1,3,6,823,-35}));
^~~~~
test.cpp:21:11: note: suggested alternative:
In file included from /usr/include/c++/8/string:51,
from /usr/include/c++/8/bits/locale_classes.h:40,
from /usr/include/c++/8/bits/ios_base.h:41,
from /usr/include/c++/8/ios:42,
from /usr/include/c++/8/ostream:38,
from /usr/include/c++/8/iostream:39,
from test.cpp:1:
/usr/include/c++/8/bits/range_access.h:105:37: note: ‘std::begin’
template<typename _Tp> const _Tp* begin(const valarray<_Tp>&);
^~~~~
Why does ADL work with a named initializer_list
(i.e. list
in the example above) but fail with an unnamed one?
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