Calling std::move without move constructor or move assignment

We know that std::move does not actually move anything. It just cast an lvalue reference (&) to rvalue reference (&&).

Then how in the following example, the copy constructor is called? If there is not move constructor, how does constructing an object that is using std::move() falls back on copy constructor? Exactly how does this binding for variable b happen?

struct Test {
  // Default constructor
  Test() {
    std::cout << "Constructor is called." << std::endl;
    mValue = 0;
  }
  
  // Copy constructor
  Test(const Test& rhs) {
    std::cout << "Copy Constructor is called." << std::endl;
    mName = rhs.mName;
    mValue = rhs.mValue;
  }
    
  std::string mName;
  int mValue;
};

int main() {
  Test a;
  Test b = std::move(a);
  return 0;
}

Output:

Constructor is called.
Copy Constructor is called.