Code:
void function(array<int,3> * ptr)
{
int temp = ptr[2]; // Error
int temp = (*ptr)[2]; // Can work!
}
int main(void)
{
array<int,3> arr={1,2,3};
function(&arr);
return 0;
}
I have no idea why the pointer cannot work like this:
int *a = new int[3];
a[2];
Thanks for your answer.
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