lambdas and `const std::function&` arguments - minimizing copies

If I have code like this:

int executeTypeErased(const std::function<int()>& f)
{
    return f();
}

void test()
{
    executeTypeErased([] {
        return 42;
    });
}

When I call test(), am I guaranteed that no heap allocations occur due to the std::function? I know that I am guaranteed that no heap allocations occur if I wrap this in a std::reference_wrapper, but I'm less certain with an undecorated lambda as an argument, promoted to std::function.