I was learning about move semantics and rvalue references when I came across this web page https://www.open-std.org/JTC1/SC22/WG21/docs/papers/2006/n2027.html. There is a piece of code that confuses me.
Without move semantics
template <class T> swap(T& a, T& b)
{
T tmp(a); // now we have two copies of a
a = b; // now we have two copies of b
b = tmp; // now we have two copies of tmp (aka a)
}
With move semantics
template <class T> swap(T& a, T& b)
{
T tmp(std::move(a));
a = std::move(b);
b = std::move(tmp);
}
How can we perform two copies of a
b
and tmp
. Specially a
and b
since they are passed by reference.
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