C++ auto deduction of return type

I want to write a function that return different types based on different input as below.

enum MyType
{
    A,
    B
};

template<MyType T> struct MyStruct
{

};

static auto createMyStruct(MyType t)
{
    if(t==A)
        return MyStruct<A>();
    else
        return MyStruct<B>();
}

It didn't work out because there are two return types for one auto. Is there any other way to do this?