How to construct a new vector/set of pointer from another vector/set of object?

Background

I wanted to manipulate the copy of a vector, however doing a vector copy operation on each of its element is normally expensive operation.

There are concept called shallow copy which I read somewhere is the default copy constructor behavior. However I'm not sure why it doesn't work or at least I tried to do the copy of vector object and the result looks like a deep copy.

struct Vertex{
    int label;
    Vertex(int label):label(label){ }
};

int main(){
    vector<Vertex> vertices { Vertex(0), Vertex(1) };

    // I Couldn't force this to be vector<Vertex*>      
    vector<Vertex> myvertices(vertices); 

    myvertices[1].label = 123;

    std::cout << vertices[1].label << endl; 
    // OUTPUT: 1 (meaning object is deeply copied)

    return 0;
}

Naive Solution: for pointer copy.

int main(){
    vector<Vertex> vertices { Vertex(0), Vertex(1) };

    vector<Vertex*> myvertices;
    for (auto it = vertices.begin(); it != vertices.end(); ++it){
        myvertices.push_back(&*it);
    }

    myvertices[1].label = 123;

    std::cout << vertices[1].label << endl;
    // OUTPUT: 123 (meaning object is not copied, just the pointer)

    return 0;
}

Improvement

Is there any other better approach or std::vector API to construct a new vector containing just the pointer of the original vector?