Is it possible to call a member function for every type in a tuple?

namespace details {
template <std::size_t I = 0, typename Tuple, typename Function, typename... Args>
typename std::enable_if<I == std::tuple_size<Tuple>::value, void>::type ForEach(Tuple &t, Function f, Args &... args) {}

template <std::size_t I = 0, typename Tuple, typename Function, typename... Args>
typename std::enable_if<(I < std::tuple_size<Tuple>::value), void>::type ForEach(Tuple &t, Function f, Args &... args) {
    f(std::get<I>(t), args...);
    ForEach<I + 1>(t, f, args...);
}
}

An implementation for ForEach functionality for all types of a tuple is above. It calls f(tuple_type, args...)

However I want something like tuple_type.f(args...) where f and args are template arguments.

f would be a member function of all the types in the tuple, taking args... as arguments.

template <typename... Types>
class TupleManager {
    std::tuple<Types...> t;
    template <typename Function, typename... Args>
    void ForEach(Function f, Args& ... args) {
         details::ForEach<>(t, f, args...);
    }
}