I am having a hard time understanding why following code blocks:
{
std::async(std::launch::async, [] { std::this_thread::sleep_for(5s);
// this line will not execute until above task finishes?
}
I suspect that std::async returns std::future as temporary which in destructor joins on the task thread. Is it possible?
Full code is below:
int main() {
using namespace std::literals;
{
auto fut1 = std::async(std::launch::async, [] { std::this_thread::sleep_for(5s); std::cout << "work done 1!\n"; });
// here fut1 in its destructor will force a join on a thread associated with above task.
}
std::cout << "Work done - implicit join on fut1 associated thread just ended\n\n";
std::cout << "Test 2 start" << std::endl;
{
std::async(std::launch::async, [] { std::this_thread::sleep_for(5s); std::cout << "work done 2!" << std::endl; });
// no future so it should not join - but - it does join somehow.
}
std::cout << "This shold show before work done 2!?" << std::endl;
}
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