Can I initialize a std::vector with '=' thanks to the operator overloading?

I noticed that in C++11 I can initialize a vector in the following ways(not only these):

std::vector<int> v1{0,1,2};
std::vector<int> v2={3,4,5};

I suppose that in the first line the following constructor is used:

vector( std::initializer_list<T> init,
        const Allocator& alloc = Allocator() );

My doubt is whether the second line uses the same constructor or the operator overloading of '=' is involved.

Here http://ift.tt/1t18ulj, it says that

T object = {arg1, arg2, ...};

is considered as an initializer_list, right?