Is pointer addition with an int variable different from addition with an int literal?

Consider this snippet of code, trying to check if two arrays are equal:

int arr1[5] = {1,2,3,4,5};
int arr2[5] = {1,2,3,4,5};

int *p1 = arr1;
int *p2 = arr2;

if (end(arr1) - p1 == end(arr2) - p2) // Check if sizes are equal
{
    for (size_t i = 0;
         p1 != end(arr1);
         ++i){
             if (*(p1 + i) != *(p2 + i)){ // Check if each ith element is equal
                 cout << "Arrays not equal!" << endl;
                 return 0;
             }
         }
    cout << "Arrays equal!" << endl;
    return 0;
}
else // Not equal if sizes don't match
{
    cout << "Arrays not equal!" << endl;
    return 0;
}

When I run this code, I end up getting "Arrays not equal!". So, I was looking into the if condition, when I noticed that *(p1 + i) for the first i, i.e., i = 0, seems to give a value of 32766, whereas if I write *(p1 + 0), I'm getting the first element of arr1 as expected. Why does this happen?