c++ pass a curried function to a function which receives a pointer [duplicate]

void foo(void (*)(long v)) {}

auto makeBar(long baz) {
    return [=](long v) {
        std::cout << "hello from closure " << baz;
    };
}


int main() {
   auto  bar = makeBar(2);
   foo(bar);
   return 0;
}

Hi,

I'm trying to do the above. Essentially create a curried function makeBar which receives a parameter baz. then instantiate it and pass the result to function foo.

the following does not compile. Specifically the call to foo(bar). If I remove the capture [=] it compiles, but then I can't use baz within the curry.

How can this be done?