Can a const int ref in a constructor safely bind to a literal?

I know the standard has an exception about extending the lifetime of temporaries that basically says binding a const reference in a constructor won't extend the lifetime, but does this also apply to literals? For example:

class C {
    private:
        const int& ref;
    public:
        C(const int& in)
            : ref{in}
        { }
};

If I had a function returning an object of this type

C f() {
    C c(2);
    return c;
}

Would the value of c.ref be undefined in the caller if I know it's bound to a literal?