jeudi 1 janvier 2015

How do I pass a template template that's inside a template to another template?

Brain hurt yet?


I'm working on a tuple type transformation helper, and have a problem. Either I duplicate code, or I wrap a template template. I'm having trouble getting this to work though.


Here's what I need to work with:



template<template<typename> class trans> struct no_index_transformer
{
template<size_t, typename transform_t> struct transformer
{
using t = typename trans<transform_t>::t;
};
};


no_index_transformer takes a template template of a transformer that doesn't have a size_t (index) passed to it. The internal transformer template is what I need to pass. I get an error when I do that though, and so I'm not sure what the right way to pass no_index_transformer<>::transformer is.


I get an error on the following line:



template<template<typename> class transformer, typename tuple> using transform_tuple_t
= transform_tuple_index<no_index_transformer<transformer>::transformer, 0, tuple>::t;


"Template argument for template template parameter must be a class template or type alias template."


Here's the transformer:



template<typename, typename> struct tuple_cat;
template<typename... types_one, typename... types_two> struct tuple_cat<std::tuple<types_one...>, std::tuple<types_two...>>
{
public:
using t = std::tuple<types_one..., types_two...>;
};

template<template<size_t, typename> class transformer, size_t index, typename tuple> class transform_tuple_index;
template<template<size_t, typename> class transformer, size_t index, typename current_t, typename... types> class transform_tuple_index<transformer, index, std::tuple<current_t, types...>>
{
using current = std::tuple<typename transformer<index, current_t>::t>;
using next = typename transform_tuple_index<transformer, index + 1, std::tuple<types...>>::t;
using combined = typename tuple_cat<current, next>::t;
static constexpr bool test_{ std::is_same<std::tuple<void>, next>::value };

public:
using t = typename std::conditional<test_, current, combined>::type;
};
template<template<size_t, typename> class transformer, size_t index> class transform_tuple_index<transformer, index, std::tuple<>>
{
public:
using t = std::tuple<void>;
};


I'd rather not have to write and maintain multiple versions of the transformer, which is why I'd like to use a wrapper to convert an incoming template to one that takes an unused size_t.


Is there a way for me to properly pass this template?


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