Visual studio - workaround error c2770 on std::enable_if

taking the answer from here : iterate over tuple regarding printing std::tuple components, here is the code :

template<std::size_t I = 0, typename... Tp>
 typename std::enable_if<I == sizeof...(Tp), void>::type
print(const std::tuple<Tp...>& t)
{ }

template<std::size_t I = 0, typename... Tp>
 typename std::enable_if<I < sizeof...(Tp), void>::type
    print(const std::tuple<Tp...>& t)
{
    std::cout << std::get<I>(t) << std::endl;
    print <i, Tp...> (t);
}

this compiles and works perfectly on GCC, but fails to compile on VC++ (I use visual studio 2013). the error I'm gettting :

Error   4   error C2893: Failed to specialize function template 'std::enable_if<I==1,void>::type print(const std::tuple<_Types1...> &)' 
Error   3   error C2770: invalid explicit template argument(s) for 'std::enable_if<I<1,void>::type print(const std::tuple<_Types1...> &)'   

appearntly there is a documented bug on C2770 when using std::enable_if with explicit template-arguments. some developers recommended using const int as pre-argument for the template as

const int i = I+1;
print<i,Tp...>(t);

but this does not work either. there were other solutions also such as use some macros , but they fail too.
does someone have a work around it ? I searched for a solution but found none that actually works.
thanks.