I have problem to solve. I must create function that recives 2 parametres, one is string type and other is int. I must input sentence, then one number. My program must delete word that is equal in order to that number. I wrote much of my code, but i have problem, for example if i input number one, or if my sentence contains much blank spaces between words, it does't delete them. I mustn't use iterators. This is my code.
#include <iostream>
#include <string>
#include <algorithm>
int Numberofwords(std::string s)
{
int trigg (0),suff(0);
int x(0),y(s.length()-1);
while(s[x] == ' ')
x++;
for(int x(y);x>=0;x--)
{
if(s[x]==' ') suff++;
if(s[x] != ' ') break;
}
for(;x<s.length()-suff;x++)
{
if(s[x] == ' ') trigg++;
if((s[x] == s[x+1]) && s[x] == ' ') trigg--;
if((s[x] == ' ' && s[x+1]==' \n')) trigg--;
}
trigg++;
return trigg;
}
std::string Funkcija(std::string recenica, int n)
{
int br(Numberofwords(recenica)),x(0),y(recenica.length()-1),suff(0),counter(0),trig(0);
std::string s;
if(n<1 || n>br) throw "Inputed number must be bigger than 0 and smaller then number of words in sentence.";
while(recenica[x] == ' ')
x++;
for(int i(y);i>=0;i--)
{
if(recenica[i] == ' ') suff++;
if(recenica[i] != ' ') break;
}
int a(x);
for(;a<recenica.length()-suff;a++)
{
if(recenica[a] == ' ') trig++;
if(trig == (n-1))
{
int e(a);
while(recenica[e+1] != ' ')
{
counter++;
e++;
}
recenica.erase(a+1,counter);
}
}
return recenica;
}
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