Attempting to create an overloaded operator for cout for a class (learning C++) and receiving the following errors: ..\Vpet.h:17:14: error: 'ostream' in namespace 'std' does not name a type ..\VPet.cpp:48:6: error: 'ostream' in namespace 'std' does not name a type
I have a feeling it's a syntax error, but i'm not sure. It appears to be correct so it's plausible that it could be a compiler/IDE problem. I'm using MinGW GCC compiler with Eclipse. Code Below:
Header File (IDE notifies of an error on the friend
declaration
* Vpet.h
*
* Created on: May 18, 2016
* Author: TAmend
*/
#ifndef VPET_H_
#define VPET_H_
class VPet
{
public:
friend std::ostream& operator<<(std::ostream& os, const VPet& vp);
// Constructors (Member Functions)
VPet(int weight, bool hungry);
//Default value in case the user creates a virtual pet without supplying parameters
VPet();
// Member functions
void feedPet(int amountOfFood);
bool getHungry();
double getWeight();
private:
// Data Members
double weight;
bool hungry;
};
#endif /* VPET_H_ */
Class Source File (Error notification from IDE on std::ostream& operator<<(std::ostream& os, const VPet& vp)
line
#include "Vpet.h"
#include <cmath>
//Creation of our constructor (you can leave out the initializer list,
//but without it you're initializing to default and then overriding (operation twice))
VPet::VPet(int w, bool hun):weight(w),hungry(hun)
{
}
VPet::VPet():weight(100), hungry(true)
{
}
//Member Functions
void VPet::feedPet(int amt)
{
if(amt >= (0.5 * weight))
{
hungry = false;
}
else
{
hungry = true;
}
weight = weight + (0.25 * amt);
}
double VPet::getWeight()
{
return weight;
}
bool VPet::getHungry()
{
return hungry;
}
std::ostream& operator<<(std::ostream& os, const VPet& vp)
{
std::string hungerStatus = "";
if(vp.hungry)
{
hungerStatus = "hungry";
}
else
{
hungerStatus = "not hungry";
}
return os << "weight: " << vp.weight << " hunger status: " << hungerStatus << std::endl;
}
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