**Here's a question from a competitive coding platform.I Think I have attempted it correctly. I solved it manually and cross checked the result. But its not getting accepted. Even a small help will be appreciated **
2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible(divisible with no remainder) by all of the numbers from 1 to N?
Input Format
First line contains T that denotes the number of test cases. This is followed by lines, each containing an integer,N .
Output Format
Print the required answer for each test case.
Constraints
1 <= T <= 10
1<= N<= 40
#include<bits/stdc++.h>
using namespace std;
long long int calculate_HCF( long long int a , long long int b)
{
if( b == 0)
return a;
else
return calculate_HCF(b , a%b);
}
long long int calculate_LCM( long long int a , long long int b)
{
long long int HCF = calculate_HCF(a , b);
long long int LCM = (a*b)/HCF;
return LCM;
}
int main()
{
int T;
int n;
long long int LCM=1;
scanf("%d" , &T);
{
for ( int i = 0 ; i < T ; i++)
{
scanf("%d" , &n);
if( n == 1)
{
printf("%d\n",1);
continue;
}
for( long long int p = 2 ; p <= n ; p++)
{
LCM = calculate_LCM(LCM , p);
}
printf("%lld\n",LCM);
}
}
return 0;
}
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