jeudi 22 septembre 2016

calling base class method from polymorphic base pointer is slow

The title's pretty confusing.. Here's a minimal code to sum it up -

#include <iostream>
#include <chrono>
#include <memory>

using namespace std;
using namespace std::chrono;

enum class TYPE {base, child};

class Base {
    int n;
  protected: Base(int _n) : n(_n) {}
  public: virtual TYPE getType(){ return TYPE::base; }
};

class Child: public Base {
    int m;
  public:
    TYPE getType(){ return TYPE::child; }
    Child(int _n, int _m) : Base(_n), m(_m) {}
};

int main() {
    unique_ptr<Base> b = make_unique<Child>(6, 7);
    TYPE tB = TYPE::base;
    TYPE tC = TYPE::child;

    {
        auto t1 = high_resolution_clock::now();

        std::cout << (tB == b->Base::getType()) << ", ";

        auto t2 = high_resolution_clock::now();
        auto duration = duration_cast<microseconds>( t2 - t1 ).count();
        cout << "Duration: " << duration << std::endl;

    }

    {
        auto t1 = high_resolution_clock::now();

        std::cout << (tC == b->getType()) << ", ";

        auto t2 = high_resolution_clock::now();
        auto duration = duration_cast<microseconds>( t2 - t1 ).count();
        cout << "Duration: " << duration << std::endl;

    }

    return 0;
}

And the output is as follows -

1, Duration: 12  // first run was 62
1, Duration: 0

I understand how virtual functions might be little slower in comparison to normal(compileTime-resolved) functions, but how come the above function - b->Base::getType() is sooo slower than virtual method - b->getType()? Is it doing two trips, like virtually resolving the function and then going back up to base class? Could anyone help me understand this?

IDEONE

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