I wrote a simple c++ program using explicit instantiation technique as below:
// foo.hpp
#include <iostream>
struct foo
{
template <typename Arg>
static void call(Arg arg)
{
std::cout << "foo\n";
}
};
here I have the explicit instantiation of class foo:
// foo.cc
#include "foo.hpp"
template void foo::call(int);
and in the main file I use the extern keyword to tell the compiler the foo::call is already instantiated, so there is no need to compile it again:
// main.cc
#include <iostream>
#include "foo.hpp"
extern template void foo::call(int);
int main(int argc, char const *argv[])
{
foo::call(1);
return 0;
}
I test the program with g++ and mpic++ using gcc-4.9. For g++ when I pass the foo.o it works fine:
g++ -std=c++11 -c foo.cc
g++ -std=c++11 main.cc foo.o -o main
and when I don't pass the foo.o it complains as expected:
g++ -std=c++11 test_simple.cc -o test_simple
/tmp/ccclcKnc.o: In function `main':
test_simple.cc:(.text+0x15): undefined reference to `void foo::call<int>
(int)'
collect2: error: ld returned 1 exit status
but when I compile with mpic++ (MPICH) in both cases(either passing or not passing the foo.o) the program compiles which should complain when the foo.o is not passed.
mpic++ -std=c++11 -c foo.cc
mpic++ -std=c++11 main.cc foo.o -o main
or
mpic++ -std=c++11 main.cc -o main // this line shouldn't compile but it does
I tested the code with OpenMPI and the behavior is same as g++. So the question is why the MPICH ignores the extern and compiles the instantiation again.
Thanks,
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