I have the following code to extract the left & right part from a string of type
[3->1],[2->2],[5->3]
My code looks like the following
#include <iostream>
#include <regex>
#include <string>
using namespace std;
int main()
{
regex expr("([[:d:]]+)->([[:d:]]+)");
string input = "[3->1],[2->2],[5->3]";
const std::sregex_token_iterator end;
int submatches[] = { 1, 2 };
string left, right;
for (std::sregex_token_iterator itr(input.begin(), input.end(), expr, submatches); itr != end;)
{
left = ((*itr).str()); ++itr;
right = ((*itr).str()); ++itr;
cout << left << " " << right << endl;
}
}
Output will be
3 1
2 2
5 3
Now I am trying to extend it so that first part will be a string instead of digit. For example, the input will be
[(3),(5),(0,1)->2],[(32,2)->6],[(27),(61,11)->1]
And I need to split it as
(3),(5),(0,1) 2
(32,2) 6
(27),(61,11) 1
Basic expressions that I tried ("(\(.*+)->([[:d:]]+)") just splits the entire string to two as following
(3),(5),(0,1)->2],[(32,2)->6],[(27),(61,11) 1
Can somebody give me some suggestions on how to achieve this? Appreciate all the help.
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