Is it possible to perform I/O in constexpr functions

#include <iostream>

class test
{
public:
    constexpr void setX(int val);
private:
    int x;
};

constexpr void test::setX(int val)
{
    x = val;
    std::cout << "x : " << x << '\n';
}

int main()
{
    test obj;
    obj.setX(5);
    return 0;
}

Here the question is, I am not able to perform I/O operations for degubbing in this constexpr function. So is there any way to do I/O opeartions inside the constexpr function or is this is a limitation/behaviour in C++?