mercredi 24 octobre 2018

Why is std::allocator::deallocate not noexcept?

The C++ specification (ISO/IEC 14882:2011 + ISO/IEC 14882:2014) defines in Table 28 — Allocator requirements for deallocate:

All n T objects in the area pointed to by p shall be destroyed prior to this call. n shall match the value passed to allocate to obtain this memory. Does not throw exceptions. But why is deallocate still not noexcept?

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