Why is void B::f() const & chosen when void B::f() const && is not present?

#include <iostream>

struct A
{
    void f() const &
    {
        std::cout << "A::f()&" << std::endl;
    }

    void f() const &&
    {
        std::cout << "A::f()&&" << std::endl;
    }
};

struct B
{
    void f() const &
    {
        std::cout << "B::f()&" << std::endl;
    }
};

int main()
{
    A{}.f();
    B{}.f();
}

The output is:

A::f()&&

B::f()&

Note that void B::f() const && doesn't exist.

My questions is:

Why is void B::f() const & chosen when void B::f() const && is not present?