I have a template class called Vector
which has an exactly three-member variable of type = template argument type.
I have learned about the initializer list constructor from here: (Brace-enclosed initializer list constructor). I wanted to apply this technique with the SFINE std::enable_if
.
That means I want to construct an object if and only if the user provides three parameters to the Vector
class's constructor.
Following is my attempt:
#include <initializer_list>
#include <type_traits>
template<typename T> class Vector
{
private:
T m_x, m_y, m_z;
public:
template<typename U = std::initializer_list<T>,
typename std::enable_if_t<U::size() == 3>
>
constexpr Vector(const T &list)
{
auto iter = list.begin();
m_x = *iter;
m_y = *(++iter);
m_z = *(++iter);
}
};
int main()
{
Vector<int> vec = { 1, 2, 3 };
return 0;
}
But I am getting the following errors:
error C2064 : term does not evaluate to a function taking 0 arguments
note: see reference to class template instantiation 'Vector<int>' being compiled
error C2440 : 'initializing' : cannot convert from 'initializer list' to 'Vector<int>'
note: No constructor could take the source type, or constructor overload resolution was ambiguous
My question is:
What is the error message saying about? I am a newbie, learning things from tutorials and books. I could not understand the meaning. Sorry, if its too obvious error message.
Can we restrict construction/ instantiation of the Vector
class, if and only if, the user provides three arguments to the initializer_list constructor?
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