Why values of array cannot be printed using foreach loop in called function when array is passed as argument in caller function? [duplicate]

This question already has an answer here:

• Range based for-loop on array passed to non-main function 2 answers

I am trying to print values of array in called function using foreach loop but facing compilation error. Using c++11 compiler in linux platform and using VIM editor.

Tried using C-style for loop and it worked, when the size is passed from calling function

#include <iostream>
using namespace std;

void call(int [], int);

int main()
{
    int arr[] = {1,2,3,4,5};
    int size = sizeof(arr)/sizeof(arr[0]);
    call(arr,size);
}

void call(int a[],int size)
{    
    for(int i =0 ; i<size; i++)
        cout << a[i];
}

For-each loop used in the below code, which fails to compile.

#include <iostream>
using namespace std;

void call(int []);

int main()
{
    int arr[] = {1,2,3,4,5};
    call(arr);
}

void call(int a[])
{
    for ( int x : a ) 
        cout << x << endl;
}

For-each loop in C++11 expects to know the size of array to iterate ? If so, how it will be helpful with respect to traditional for loop. Or something wrong i coded here?

I would look forward for your help. Thanks in advance.