Why operator* of rvalue unique_ptr returns lvalue?

Using the return value of operator* from a "dead" unique_ptr is bad.

The following code compiles but results of course with an Undefined Behavior:

auto& ref = *std::make_unique<int>(7);
std::cout << ref << std::endl;

Why the standard didn't make the return value of operator* for rvalue of std::unique_ptr an rvalue of the internal value, instead of lvalue, like that:

// could have been done inside unique_ptr
T& operator*() & { return *ptr; }
T&& operator*() && { return *ptr; }

In which case this would work fine:

std::cout << *std::make_unique<int>(7) << std::endl;

But the code at the beginning would not compile (cannot bind rvalue to lvalue).

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Side note. Of course someone could still write bad code like the below, but it is saying "I'm UB" more verbosely, thus not so relevant:

auto&& ref = *std::make_unique<int>(7);
std::cout << ref << std::endl;

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Is there any good usage of operator* on rvalue of std::unique_ptr, returning lvalue ref?