Call a function with std::function as argument with a lambda

The basis from my question I took from here: Failure to deduce template argument std::function from lambda function The question in this thread is: Why this code can't pass the lambda to the function:

#include <iostream>
#include <functional>

template <typename T>
void call(std::function<void(T)> f, T v)
{
    f(v);
}

int main(int argc, char const *argv[])
{
    auto foo = [](int i) {
        std::cout << i << std::endl;
    };
    call(foo, 1);
    return 0;
}

The answer in this thread is, since a lambda isn't a std::function. But why is this code compiling:

#include <iostream>
#include <functional>

template <typename T>
void call(std::function<void(T)> f, T v)
{
    f(v);
}

int main(int argc, char const *argv[])
{
    auto foo = [](int i) {
        std::cout << i << std::endl;
    };
    call({foo}, 1); // changed foo to {foo}
    return 0;
}