How member function with variadic parameters as template parameter

Is it possible to write template function in C++14 like below

Here is the sample https://godbolt.org/z/9gRk-t

// pseudo code

#include <type_traits>

template <typename T, typename R, typename... Args>
decltype(auto) Call(T& obj, R(T::*mf)(Args...), Args&&... args) 
{
  return (obj.*mf)(std::forward<Args>(args)...);
}

So, for a test class

struct Test 
{
  int Func(){return 1;};
  bool Func(bool){return true;};  // overload

  void FuncInt(int){};
};

The template coudl work for the use case below (but it failed)

int main()
{
  Test test;

  // for overload case
  auto a = Call<int()>(test, &Test::Func);
  auto b = Call<bool(bool)>(test, &Test::Func, true);

  // for non-overload case
  Call(test, &Test::FuncInt, 1);

  return 0;
}

Herer the erro info.

#1 with x64 msvc v19.24
example.cpp
<source>(23): error C2672: 'Call': no matching overloaded function found
<source>(23): error C2770: invalid explicit template argument(s) for 'decltype(auto) Call(T &,R (__cdecl T::* )(Args...),Args &&...)'
<source>(5): note: see declaration of 'Call'
<source>(24): error C2672: 'Call': no matching overloaded function found
<source>(24): error C2770: invalid explicit template argument(s) for 'decltype(auto) Call(T &,R (__cdecl T::* )(Args...),Args &&...)'
<source>(5): note: see declaration of 'Call'
Compiler returned: 2