#include <iostream>
struct Foo {
template <int bias = 5>
void print() {
std::cout << bias << std::endl;
}
};
template <int bias = 5>
std::ostream &operator<<(std::ostream &os, const Foo &foo) {
return os << bias;
}
int main() {
Foo a;
a.print();
a.print<>();
a.print<1>();
std::cout << a << std::endl;
return 0;
}
By showing this code, I mean, despite the terrible implementation, is there a way to change the default parameter 5
while using std::cout
and keeping the struct
unchanged?
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