I have a template vec<T> class for math vectors with constant length is equal to 3. It looks like this:
template <typename T>
class vec{
public:
    vec() { /**/ }
    vec(std::initializer_list<T> list) { /**/ }
private:
    std::array<T, 3> data;
};
I know, that it is possible to initialize std::array with an std::initializer_list in such a way:
std::array<int, 3> a = {1, 2, 3};
So I would like to have a constructor with an std::initializer_list to initialize my vector like this:
vec<int> v = {1, 2, 3};
I also have a solution for this: just iterate through std::initializer_list elements and write to data:
vec(std::initializer_list<T> list) {
    size_t i = 0;
    for (auto it = list.begin(); it != list.end(); it++) {
        data[i++] = *it;
    }
}
I tried to make constructor look like this (because of std::array has a constructor with std::initializer_list):
vec(std::initializer_list<T> list) {
    data = list;
}
But when I try to compile a program, the error occurs:
no match for ‘operator=’ (operand types are ‘std::array<int, 3>’ and ‘std::initializer_list<int>)’
What's the problem here? Why can't I initialize std::array with initializer list in such a way?
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