Question is The user enters three negative integers A, B and C. Display in reverse order all
numbers from the interval from A to B that are less than C (A <B, positive order - increasing, reverse order - decreasing).
int reversDigits(int num)
{
int rev_num = 0;
while (num > 0)
{
rev_num = rev_num*10 + num%10;
num = num/10;
}
return rev_num;
}
/* Driver program to test reversDigits */
int main()
{
int num = 5896;
printf("Reverse of no. is %d", reversDigits(num));
return 0;
}
Aucun commentaire:
Enregistrer un commentaire