Understanding const auto pointers [duplicate]

This question already has an answer here:

• How does const auto and auto const apply to pointers? 1 answer

Consider:

int main()
{
    int * i0 = new int;
    *i0 = 666; // OK

    const int * i1 = new int;
    *i1 = 666; // FAIL due to const

    auto i2 = new int;
    *i2 = 666; // OK

    const auto i3 = new int;
    *i3 = 666; // OK, WHY?

    const auto * i4 = new int;
    *i4 = 666; // FAIL due to const

    return 0;
}

Why does case i3 work? I have always thought that in this case const auto would be implicitly const int * but I guess this is not the case?