How to automatically convert a lambda to a std::function?

In C++11+ one can write something like this:

#include <functional>

std::function<float(int)> f = [](int i){ return i / 100.0; };

Is there a way to write a function make_std_function (possibly using templates) which allows to create a std::function object in the following manner:

auto f = make_std_function([](int i){ return i / 100.0; });