I'm using boost::irange
and created a helper function to simplify the code by removing the need for explicit template parameters. I don't understand why it doesn't work. Here's the code:
#include <iostream>
#include <boost/range/irange.hpp>
template<typename T>
boost::irange<T> range_from_zero(T limit)
{
return boost::irange<T>(T(), limit);
}
int main() {
size_t end = 100;
for (auto i : range_from_zero(0,end))
std::cout << i << ' ';
return 0;
}
There's a live version here http://ift.tt/1DMoQot, which produces compilation errors
prog.cpp:5:8: error: 'irange<T>' in namespace 'boost' does not name a type
boost::irange<T> range_from_zero(T limit)
^
prog.cpp: In function 'int main()':
prog.cpp:12:41: error: 'range_from_zero' was not declared in this scope
for (auto i : range_from_zero(0,end))
If I use boost::irange
directly in the range-for, then it works:
#include <iostream>
#include <boost/range/irange.hpp>
int main() {
size_t end = 100;
for (auto i : boost::irange<size_t>(0,end))
std::cout << i << ' ';
return 0;
}
this works fine: http://ift.tt/1OI0bfd
I thought maybe is was a problem using range-for on the return of a function, but it isn't; this works using a std::vector
:
#include <iostream>
#include <boost/range/irange.hpp>
template<typename T>
std::vector<T> range_from_zero(T limit)
{
auto range = boost::irange<T>(T(), limit);
return { std::begin(range), std::end(range) };
}
int main() {
size_t end = 100;
for (auto i : range_from_zero(end))
std::cout << i << ' ';
return 0;
}
Any ideas, please?
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