Consider this fully working code:
#include <type_traits>
template <typename T, typename IndexPack> struct Make;
template <typename T, template <T...> class P, T... Indices>
struct Make<T, P<Indices...>> {
using type = P<(Indices+1)..., (-3*Indices)..., (Indices-1)...>;
};
template <int...> class Pack;
int main() {
static_assert (std::is_same<Make<int, Pack<1,2,3,4>>::type,
Pack<2,3,4,5, -3,-6,-9,-12, 0,1,2,3>>::value, "false");
}
What I actually want the output to be is
Pack<2,-3,0, 3,-6,1, 4,-9,2, 5,-12,3>
instead of Pack<2,3,4,5, -3,-6,-9,-12, 0,1,2,3>
. I first tried
using type = P<(Indices+1, -3*Indices, Indices-1)...>;
but that is simply understood by the compiler to be a useless comma operator. What is the desired syntax to get what I want? If there is no such syntax, what is the cleanest way to do this, keeping in mind that using Indices
3 times is just an example (we may want to use it more than 3 times). Please don't tell me that I have to write a helper to extract the individual packs and then "interlace" all the elements. That nightmarish method cannot be the best solution (and such a solution would also only work if we knew exactly how many individual packs to extract).
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