Dangling reference in inner lambda

I have an inner lambda that uses one of the referenced variables of the outer lambda like this:

int x=0;
auto outer=[&](){
   return [&](){
        x=5;
    };
};

auto inner= outer();
inner();
std::cout << x;

I tried it. It worked well. However, I want to make sure that there is no dangling reference here. Is there?