Different behavior of Visual Stuido and gcc when compiling variadic templates program

I'm playing with C++11's variadic templates, and here is my code:

#include "iostream"
void func(){
    std::cout << std::endl;
}

template< typename ...Params> void func(int x, Params... params){
    std::cout << " int " << x;
    func(params...);
}
template< typename ...Params> void func(float x, Params... params){
    std::cout << " float " << x;
    func(params...);
}
template< typename ...Params> void func(const char* x, Params... params){
    std::cout << " const char* " << x;
    func(params...);
}

int main(int argc, char* argv[])
{
    func(3.14f, 5, "Test");
    getchar();
    return 0;
}

The code above can be compiled and run on Visual Studio 2013 without any problem, but if I compile it with gcc 4.6.3 (I don't have gcc environment and using online service like repl.it), this code will produce error like this:

main.cpp: In instantiation of 'void func(int, Params ...) [with Params = {const char*}]':
main.cpp:15:6:   required from 'void func(float, Params ...) [with Params = {int, const char*}]'
main.cpp:24:23:   required from here
main.cpp:11:6: error: no matching function for call to 'func(const char*&)'
  func(params...);
  ~~~~^~~~~~~~~~~
main.cpp:5:6: note: candidate: void func()
 void func(){
      ^~~~
main.cpp:5:6: note:   candidate expects 0 arguments, 1 provided
main.cpp:9:36: note: candidate: template<class ... Params> void func(int, Params ...)
 template< typename ...Params> void func(int x, Params... params){
                                    ^~~~
main.cpp:9:36: note:   template argument deduction/substitution failed:
main.cpp:11:6: note:   cannot convert 'params#0' (type 'const char*') to type 'int'
  func(params...);
  ~~~~^~~~~~~~~~~

exit status 1

Whose behavior is right? Is this code has some problem I don't acknowledge or this is a bug of gcc?

BTW: If I change func(3.14f,5,"test") into func(3.14f,5) then gcc can compile this code as well.