Can one use template specialization on a templated typedef?

I would like to do something like the following (in c++11, c++14; not c++17):

template <class T>
using partner = void;

template<>
using partner<A> = X;

template<>
using partner<B> = Y;

template<>
using partner<C> = Z;

But I get a compilation error---

error: expected unqualified-id before ‘using’

---on the first template specialization.

Is such a thing possible? (I already know I can use a templated class with a using statement inside it. I'm hoping directly use the using statement without the class wrapper, since it's simpler and more elegant. If there's another simple, elegant solution, please share!)