Passing a pointer-to-member function into template

I wonder how can I pass a pointer to the non-static member function into the template? Here's the simplified code:

template<typename, typename>
struct contains;

template<typename T, typename R, typename... Ts>
struct contains<T, R(Ts...)>
{
    static constexpr bool result = std::disjunction_v<std::is_same<T, Ts>...>;
};

class A
{
public:
    static void staticFoo(int a, double* b) {}
    void foo(int a, double* b) {}
};
void foo(int a, double* b) {}

int main ()
{
    //ok, this works
    std::cout << std::boolalpha << contains<double*, decltype(foo)>::result;
    //this too
    std::cout << std::boolalpha << contains<double*, std::remove_pointer_t<decltype(&A::staticFoo)>>::result;
    //boom, error
    std::cout << std::boolalpha << contains<double*, decltype(&A::foo)>::result;

    return 0;
}

Executing this code, I got an error:

 incomplete type 'contains<double*, void (A::*)(int, double*)>' used in nested name specifier

As I understood, types are:

void(int, double*)
void(*)(int, double*)
void(A::*)(int, double*)

In the second case I can use std::remove_pointer_t, but how can I remove (A::*) from function signature in the third case?