inheritance with overloading in C++ makes error: no matching function for call [duplicate]

This question already has an answer here:

• Why does implementation of abstract class not see overloaded pure virtual function? 2 answers
• Why does an overridden function in the derived class hide other overloads of the base class? 4 answers

I faced with compilation error for the following program:

#include <iostream>

class A
{
public:
    virtual void f(int i) {
        std::cout << "A::f" << std::endl;
    }
};


class B : public A
{
public:
    virtual void f(int i, int j) {
        std::cout << "B::f" << std::endl;
    }
};

class C : public B
{
public:
    virtual void f(int i) override {
        std::cout << "C::f1" << std::endl;
    }

    virtual void f(int i, int j) override {
        std::cout << "C::f2" << std::endl;
    }
};


int main(int argc, char* argv[])
{
    B * p = new C();
    p->f(1);
    return 0;
}

When compiling this with gcc version 4.8.5 20150623 (Red Hat 4.8.5-16) as:

g++ test.cpp -std=c++11

the error is:

test.cpp: In function 'int main(int, char**)':
test.cpp:37:11: error: no matching function for call to 'B::f(int)'
     p->f(1);
           ^
test.cpp:37:11: note: candidate is:
test.cpp:15:18: note: virtual void B::f(int, int)
     virtual void f(int i, int j) {
                  ^
test.cpp:15:18: note:   candidate expects 2 arguments, 1 provided

There will be no error if in main function pointer p has type C*, but why class B does not have void f(int i)? I expect it should be inherited from A and be available for B just because I can override void f(int i) in class C derived from class B.