I have written the below piece of code:
#define LOG cout << __PRETTY_FUNCTION__ << endl;
class MyClass
{
private:
int* ptr;
public:
MyClass()
: ptr(new int(10))
{
LOG
}
~MyClass()
{
LOG
if (ptr)
{
delete ptr;
ptr = nullptr;
}
}
MyClass(const MyClass& a)
: ptr(nullptr)
{
LOG
ptr = new int;
*ptr = *(a.ptr);
}
MyClass& operator=(const MyClass& a)
{
LOG
if (this == &a)
{
return *this;
}
delete ptr;
ptr = new int;
*ptr = *(a.ptr);
return *this;
}
MyClass(MyClass&& a)
: ptr(nullptr)
{
LOG
ptr = a.ptr;
a.ptr = nullptr;
}
MyClass& operator=(MyClass&& a)
{
LOG
if (this == &a)
{
return *this;
}
delete ptr;
ptr = a.ptr;
a.ptr = nullptr;
return *this;
}
void deleteMe()
{
LOG
delete this;
}
void printClass()
{
LOG;
}
};
MyClass function()
{
MyClass m;
return m;
}
int main()
{
MyClass m = function();
return 0;
}
Output of the program:
MyClass::MyClass()
MyClass::~MyClass()
This does not call the move constructor. Is there something is wrong?
I was expecting the below output:
MyClass::MyClass()
MyClass::MyClass(MyClass&&)
MyClass::~MyClass()
MyClass::MyClass(MyClass&&)
MyClass::~MyClass()
MyClass::~MyClass()
It might look like the compiler is doing some optimisation. If this the case then why we need move constructor or move assignment operator for our case.
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